Author: Arun Raj
Posted: Thu Dec 15, 2016 1:12 am (GMT 5.5)
Rohit,
Yes, that was an assumption I made that all table1 IDs are available in the second table unless the OP has stated otherwise, or what he wants in such a scenario.
Apart from that, the interpretations are different here. My understanding was like this, the OP can clarify if it is incorrect.
Let's say an ID=ID1 has the CODEs A,B,C,E,F. Since it has ANY one of the 'valid' IDs, my output will have only these:
Let's say another ID=ID2 has the CODEs E,F,G,H since none of them falls in the list of 'valid' CODEs, so the output will have these:
I see your code will give this for Case1:
I'd wait for the OP to clarify the requirement before we proceed any further.
_________________
Arun
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Love is like an hourglass, with the heart filling up as the brain empties. -Jules Renard
Posted: Thu Dec 15, 2016 1:12 am (GMT 5.5)
Rohit,
Yes, that was an assumption I made that all table1 IDs are available in the second table unless the OP has stated otherwise, or what he wants in such a scenario.
Apart from that, the interpretations are different here. My understanding was like this, the OP can clarify if it is incorrect.
Let's say an ID=ID1 has the CODEs A,B,C,E,F. Since it has ANY one of the 'valid' IDs, my output will have only these:
| Code: |
| ID1 A ID1 B ID1 C |
Let's say another ID=ID2 has the CODEs E,F,G,H since none of them falls in the list of 'valid' CODEs, so the output will have these:
| Code: |
| ID2 X |
I see your code will give this for Case1:
| Code: |
| ID1 A ID1 B ID1 C ID1 X ID1 X |
_________________
Arun
----------------------------------------------------------------------------------------------------
Love is like an hourglass, with the heart filling up as the brain empties. -Jules Renard